Saturday, October 13, 2012

Get all fields for XSLT webpart in SharePoint 2010




Place this in an xslt on the server, then link it in the dataview web part

 

       
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:x="http://www.w3.org/2001/XMLSchema" xmlns:d="http://schemas.microsoft.com/sharepoint/dsp" version="1.0" exclude-result-prefixes="xsl msxsl ddwrt" xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" xmlns:asp="http://schemas.microsoft.com/ASPNET/20" xmlns:__designer="http://schemas.microsoft.com/WebParts/v2/DataView/designer" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:SharePoint="Microsoft.SharePoint.WebControls" xmlns:ddwrt2="urn:frontpage:internal" xmlns:o="urn:schemas-microsoft-com:office:office">
<xsl:include href="/_layouts/xsl/main.xsl"/>
<xsl:include href="/_layouts/xsl/internal.xsl"/>
<xsl:template match="/">
   <textarea rows="20" cols="100">
       <xsl:apply-templates/>
   </textarea>
</xsl:template>
<xsl:template match="node()|@*">
   <!-- Copy the current node -->
       <xsl:copy>
       <!-- Including any child nodes it has and any attributes -->
       <xsl:apply-templates select="node()|@*"/>
   </xsl:copy>
</xsl:template>
</xsl:stylesheet>

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